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engineering mechanics force vectors
1. Express force F as a Cartesian vector; then determine its direction angles.
(A): F = (-2i +j+2k) kN, = 131.8°, = 70.5°, = 48.2°
(B): F = (-2i +j+2k) kN, = 48.2°, = 70.5°, = 48.2°
(C): F = (-4i +2j+4k) kN, = 131.8°, = 70.5°, = 48.2°
(D): F = (-4i +j+4k) kN, = 48.2°, = 70.5°, = 48.2°
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