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1. What will be the output of the program? public class ThreadDemo { private int count = 1; public synchronized void doSomething() { for (int i = 0; i < 10; i++) System.out.println(count++); } public static void main(String[] args) { ThreadDemo demo = new ThreadDemo(); Thread a1 = new A(demo); Thread a2 = new A(demo); a1.start(); a2.start(); } } class A extends Thread { ThreadDemo demo; public A(ThreadDemo td) { demo = td; } public void run() { demo.doSomething(); } }





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  • By: guest on 02 Jun 2017 01.26 am
    You have two different threads that share one reference to a common object. The updating and output takes place inside synchronized code. One thread will run to completion printing the numbers 1-10. The second thread will then run to completion printing the numbers 11-20.
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