1. Brass and copper pipe should be joined with fittings of copper-base alloy to avoid corrosion.



Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->What is the name for the greenblue coating that forms naturally on copper; bronze and brass?....
QA->A small piece of wire made from an alloy of lead and tin is used to avoid overloading is?....
QA->Great Britain and Northern Ireland joined together and became United Kingdom of Great Britain and Ireland by ?....
QA->P and Q can complete a work in 20 days and 12 days respectively. P alone started the work and Q joined him after 4 days till the completion of the work. How long did the work last?....
QA->The most corrosion-resistant metal?....
MCQ->Each of the seven friends viz. P,Q,R,S,T,U and V joined seven different courses viz. MBA, MBBS, Law, Engineering, Arts, Science and Commerce (None of the given information necessarily in the same order) on seven different days of the same week i.e., Monday to Sunday. Only three people joined after S. Only two people joined between S and the one who joined Law. Only three people joined between the one who joined law and the one who joined Engineering. Only one person joined between V and the one who joined Arts. V joined before the person who joined Arts. V neither joined on Tuesday nor Wednesday. V did not join Engineering. Only three people joined between V and R. P joined on the day immediately before the one who joined Commerce. Neither S nor T joined Commerce. Q joined MBBS. P did not join Science. Qs.The one who joined Science, joined in which of the following days ?....
MCQ->Brass and copper pipe should be joined with fittings of copper-base alloy to avoid corrosion.....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { int x, y; public: Base() { x = y = 0; } Base(int xx) { x = xx; } Base(int p, int q = 10) { x = p + q; y = q; } void Display(void) { cout<< x << " " << y << endl; } }objDefault(1, 1); class Derived: public Base { Base obj; public: Derived(int xx, int yy): Base(xx, xx + 1) { } Derived(Base objB = objDefault) { } }; int main() { Derived objD(5, 3); Derived ptrD = new Derived(objD); ptrD->Display(); delete ptrD; return 0; }....
MCQ->Which of the following conditions must be satisfied for a transistor to remain under saturation? Its collector to base junction should be under forward bias.Its collector to base junction should be under reverse bias.Its emitter to base junction should be under reverse bias.Its emitter to base junction should be under forward bias. Select the correct answer from the codes given below:....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { public: int S, A, M; Base(int x, int y) { S = y - y; A = x + x; M = x x; } Base(int, int y = 'A', int z = 'B') { S = y; A = y + 1 - 1; M = z - 1; } void Display(void) { cout<< S << " " << A << " " << M << endl; } }; class Derived : public Base { int x, y, z; public: Derived(int xx = 65, int yy = 66, int zz = 67): Base(x) { x = xx; y = yy; z = zz; } void Display(int n) { if(n) Base::Display(); else cout<< x << " " << y << " " << z << endl; } }; int main() { Derived objDev; objDev.Display(-1); return 0; }....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution