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What will be the output of the program ? #include<stdio.h> int main() { float arr[] = {12.4, 2.3, 4.5, 6.7}; printf("%d\n", sizeof(arr)/sizeof(arr[0])); return 0; } ?->(Show Answer!)
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1. What will be the output of the program ? #include<stdio.h> int main() { float arr[] = {12.4, 2.3, 4.5, 6.7}; printf("%d\n", sizeof(arr)/sizeof(arr[0])); return 0; }





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  • By: guest on 01 Jun 2017 06.00 pm
    The sizeof function return the given variable. Example: float a=10; sizeof(a) is 4 bytes Step 1: float arr[] = {12.4, 2.3, 4.5, 6.7}; The variable arr is declared as an floating point array and it is initialized with the values. Step 2: printf("%d\n", sizeof(arr)/sizeof(arr[0])); The variable arr has 4 elements. The size of the float variable is 4 bytes. Hence 4 elements x 4 bytes = 16 bytes sizeof(arr[0]) is 4 bytes Hence 16/4 is 4 bytes Hence the output of the program is '4'.
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