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What will be the output of the program if the array begins 1200 in memory? #include<stdio.h> int main() { int arr[]={2, 3, 4, 1, 6}; printf("%u, %u, %u\n", arr, &arr[0], &arr); return 0; } ?->(Show Answer!)
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1. What will be the output of the program if the array begins 1200 in memory? #include<stdio.h> int main() { int arr[]={2, 3, 4, 1, 6}; printf("%u, %u, %u\n", arr, &arr[0], &arr); return 0; }





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  • By: guest on 01 Jun 2017 06.00 pm
    Step 1: int arr[]={2, 3, 4, 1, 6}; The variable arr is declared as an integer array and initialized. Step 2: printf("%u, %u, %u\n", arr, &arr[0], &arr); Here, The base address of the array is 1200. => arr, &arr is pointing to the base address of the array arr. => &arr[0] is pointing to the address of the first element array arr. (ie. base address) Hence the output of the program is 1200, 1200, 1200
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