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What will be the output of the program? #include<stdio.h> int main() { const c = -11; const int d = 34; printf("%d, %d\n", c, d); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> int main() { const c = -11; const int d = 34; printf("%d, %d\n", c, d); return 0; }





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  • By: guest on 01 Jun 2017 06.00 pm
    Step 1: const c = -11; The constant variable 'c' is declared and initialized to value "-11". Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initialized to value '34'. Step 3: printf("%d, %d\n", c, d); The value of the variable 'c' and 'd' are printed. Hence the output of the program is -11, 34
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