Point out the error in the program. #include<stdio.h> #define MAX 128 int main() { char mybuf[] = "India"; char yourbuf[] = "BIX"; char const ptr = mybuf; ptr = 'a'; ptr = yourbuf; return 0; } ?->(Show Answer!)

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Point out the error in the program. #include<stdio.h> #define MAX 128 int main() { char mybuf[] = "India"; char yourbuf[] = "BIX"; char const ptr = mybuf; ptr = 'a'; ptr = yourbuf; return 0; } ?->(Show Answer!)

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1. Point out the error in the program. #include<stdio.h> #define MAX 128 int main() { char mybuf[] = "India"; char yourbuf[] = "BIX"; char const ptr = mybuf; ptr = 'a'; ptr = yourbuf; return 0; }

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By: guest on 01 Jun 2017 06.01 pm

Step 1: char mybuf[] = "India"; The variable mybuff is declared as an array of characters and initialized with string "India". Step 2: char yourbuf[] = "BIX"; The variable yourbuf is declared as an array of characters and initialized with string "BIX". Step 3: char *const ptr = mybuf; Here, ptr is a constant pointer, which points at a char. The value at which ptr it points is not a constant; it will not be an error to modify the pointed character; There will be an error only to modify the pointer itself. Step 4: *ptr = 'a'; The value of ptr is assigned to 'a'. Step 5: ptr = yourbuf; Here, we are changing the pointer itself, this will result in the error "cannot modify a const object".

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