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What will be the output of the program? #include<stdio.h> int main() { int i=4; switch(i) { default: printf("This is default\n"); case 1: printf("This is case 1\n"); break; case 2: printf("This is case 2\n"); break; case 3: printf("This is case ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> int main() { int i=4; switch(i) { default: printf("This is default\n"); case 1: printf("This is case 1\n"); break; case 2: printf("This is case 2\n"); break; case 3: printf("This is case 3\n"); } return 0; }





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  • By: guest on 01 Jun 2017 06.01 pm
    In the very begining of switch-case statement default statement is encountered. So, it prints "This is default". In default statement there is no break; statement is included. So it prints the case 1 statements. "This is case 1". Then the break; statement is encountered. Hence the program exits from the switch-case block.
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