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What will be the output of the program? #include<stdio.h> int main() { int i; char c; for(i=1; i<=5; i++) { scanf("%c", &c); / given input is 'a' / printf("%c", c); ungetc(c, stdin); } return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> int main() { int i; char c; for(i=1; i<=5; i++) { scanf("%c", &c); / given input is 'a' / printf("%c", c); ungetc(c, stdin); } return 0; }





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  • By: guest on 01 Jun 2017 06.02 pm
    for(i=1; i<=5; i++) Here the for loop runs 5 times. Loop 1:
    scanf("%c", &c); Here we give 'a' as input.
    printf("%c", c); prints the character 'a' which is given in the previous "scanf()" statement.
    ungetc(c, stdin); "ungetc()" function pushes character 'a' back into input stream. Loop 2:
    Here the scanf("%c", &c); get the input from "stdin" because of "ungetc" function.
    printf("%c", c); Now variable c = 'a'. So it prints the character 'a'.
    ungetc(c, stdin); "ungetc()" function pushes character 'a' back into input stream. This above process will be repeated in Loop 3, Loop 4, Loop 5.
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