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What will be the output of the program ? #include<stdio.h> int main() { char str[25] = "IndiaBIX"; printf("%s\n", &str+2); return 0; } ?->(Show Answer!)
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1. What will be the output of the program ? #include<stdio.h> int main() { char str[25] = "IndiaBIX"; printf("%s\n", &str+2); return 0; }





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  • By: guest on 01 Jun 2017 06.02 pm
    Step 1: char str[25] = "IndiaBIX"; The variable str is declared as an array of characteres and initialized with a string "IndiaBIX". Step 2: printf("%s\n", &str+2); => In the printf statement %s is string format specifier tells the compiler to print the string in the memory of &str+2 => &str is a location of string "IndiaBIX". Therefore &str+2 is another memory location. Hence it prints the Garbage value.
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