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1. What will be the output of the program ? #include<stdio.h> int main() { char str = "IndiaBIX"; printf("%s\n", str); return 0; }





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  • By: guest on 01 Jun 2017 06.02 pm
    The line char str = "IndiaBIX"; generates "Non portable pointer conversion" error. To eliminate the error, we have to change the above line to char *str = "IndiaBIX"; (or) char str[] = "IndiaBIX"; Then it prints "IndiaBIX".
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