57652. What are units of width and height specified in HTML tag?
57653. A D-flip-flop is
57654. The fetching, decoding and executing of an instruction is broken down into several time intervals. Each of these intervals, involving one or more clock periods, is called a
57655. The output of the circuit shown below will be of the frequency
57656. In the given figure Y =
57657. Assertion (A): An encoder converts key dips to binary code.Reason (R): An encoder has more inputs than output.
57658. If a RAM has 34 bits in its MAR and 16 bits in its MDR, then its capacity will be
57659. DeMorgan's second theorem is
57660. What will be the result of the expression 13 and 25?
57661. In floating point representation, mantissa is expressed in
57662. Crown of teeth is covered by?
57663. In the generic microprocessor
57664. Consider the following registers: A accumulator and B registerB and C registersD and E registersH and L registers Which of these 8-bit registers of 8085 μP can be paired together to make a 16-bit register?
57665. Access time of a storage is the time required
57666. For a D/A converter, inputs and outputs are given. The output corresponding to digital input 01000
57667. By placing an inverter between both inputs of an S-R flip-flop, the resulting flip-flop becomes
57668. Which of the following flip-flop do not have race problem?
57669. It is desired to route data from many registers to one register. The device needed is
57670. Advanced low power Schottky is a part of
57671. A device that converts from decimal to binary numbered is called
57672. It is desired to clean up ragged looking pulsed that have been distorted during transmission from one place to another, which of the following device will be appropriate?
57673. Decimal number 9 in gray code =
57674. In magnetic film memory, the memory element consits of
57675. Which device changes serial data to parallel data?
57676. CD4010 is a
57677. What is the terminal count in decimal form?
57678. The binary sum of 1110102 and 110112 is
57679. The number of programmable 8 bit registers of 6800 are
57680. The seven bit Hamming code received is 0010001. If even parity has been used, the correct code is
57681. When two 4 bit parallel adders are cascaded we get
57682. Consider the following features: negative operands cannot be usedwhen immediate operand changes, the program should be reassembledthe program is difficult to readthe size of operand is restricted by word length of the computer Disadvantages of immediate addressing include
57683. Which binary addition is incorrect?
57684. Flash ADC is
57685. Which of the following logic no resistors are used?
57686. With the switch in STOP position, Y will be equal to
57687. PROM is
57688. Decimal 17 in octal system is represented by
57689. The logic operation that will selectively clear bits in register A in those positions where these are 1 's in the bits of register B is given by
57690. The 2's complement representation of the decimal number -4 is
57691. The following program starts at location 0100H
L X ISP, 00FF - the content if accumulator
LXIH, 0701 - when the program counter
MVI A, 20 H - reaches 0109 H is
S ∪ BM
57692. In 8085 microprocessor, what is the length of PC (program counter)?
57693. In decimal system the base of radix is
57694. 7483 is a TTL binary adder. It can add
57695. A 12 bit ADC is operating with 1 μs clock period. Total conversion time is 14 μs. ADC is
57696. An 8156 has A15 connected to its CE input. A14 to A8 are unconnected, and AD7 to AC0 are connected ignoring shadows, what are the RAM locations?