63551. A circuit has two branches in parallel and each branch has only one element. The applied voltage and source current are v = 200 sin (200t + 30°) and i = 50 sin (200t + 50°). If one branch has capacitor, the other branch contains
63552. In the circuit shown in figure, Is = 4A, Vs = 4, the voltage V is given by
63553. The average value of wave in figure is
63554. If B = 4 + j3, (B)1/3 =
63555. A two branch parallel tuned circuit has a coil of resistance 100 Ω and inductance 0.005 H in one branch and 10 nF capacitor in the second branch. At resonance frequency, the dynamic resistance is
63556. If each branch of a Delta circuit has impedance 3 Z then each branch of the equivalent Y circuit has impedance.
63557. In the circuit of figure, Thevenin's resistance is 10 Ω
63558. An RLC series circuit has R = 1 Ω, L = 1 H, C = 1 F. The damping ratio is
63559. The circuit shown in the figure, with R = 1/3 Ω, L = 1/4H, C = 3F has input voltage v(t) = sin2t. The resulting current i(t) is
63560. If operator 'a' = 1 ∠120° then (1 + a2) =
63561. Two 2 port circuits are connected cascaded. To determine the response, it is more convenient to use
63562. In the circuit of figure. The current supplied by battery at t = ∞ is
63563. The natural frequency Sn of the given circuit is
63564. For addition and subtraction operations, phasors
63565. The equivalent unit of joule is
63566. Two coils are connected in parallel. Their fluxes are adding. If the connections of one of the coils are reversed, the total inductance of the arrangement
63567. The graph of a network has 6 branches with 3 tree branches. The minimum number of equations required for solution of network is
63568. In figure, S is closed at t = 0. At t = t1, I = 1 A and di/dt = 1 A/s. Then the value of L is
63569. In the circuit of figure, the switch is closed at t = 0. At t = 0+ the current supplied by battery is
63570. If VA = - 10 V and VB = - 15 V, VAB = 5 V.
63571. Assertion (A): Tie set schedule is used in nodal analysis.Reason (R): Loop currents are fictitious quantities.
63572. When a lead acid cell discharges, the specific gravity of electrolyte increases.
63573. For a high pass filter, β = p in attenuation band.
63574. A minimum function has
63575. The current in an RL series circuit is 1 - e-t amperes. Then di/dt is
63576. Given , and f(t)t → ∞ is . The value of k is
63577. In a one port network . It is excited by a unit step current. The initial and final values of voltage across the network impedance are
63578. In the circuit of figure, the current through battery E2 is
63579. In figure, the current supplied by battery at t = 0.5s is
63580. A source of angular frequency 1 rad sec has a source impedance consisting of 1 Ω resistance in series with 1 H inductance. The load that will obtained the maximum power transfer is
63581. When tracing through a resistance we always get a voltage drop.
63582. A copper coil has a resistance of 40 ohm at 20°C. At 100°C the resistance is likely to be
63583. Assertion (A): In a parallel circuit with three branches having R, L and C respectively and fed by a step current I, the current through inductance is always zero.Reason (R): The time constant of R-L circuit is L/R.
63584. When a source is delivering maximum power to a load through a network, the ratio of power delivered to the source power
63585. The number of electrons in motion at the instant of positive peak of a symmetrical ac wave is the same as that at the instant of negative peak.
63586. In figure, the current through R, after the steady state condition is reached, is
63587. A two branch parallel tuned circuit has 100 Ω resistance and 0.1 H inductance in one branch and 10-6 F capacitor in the other. At resonance frequency, the dynamic resistance is
63588. Special circuits using neon tubes, contact relays and capacitors are used in many domestic appliances. The role of capacitor in figure is to
63589. A series R, L, C circuit has R = 2Ω, L = 1H, C = 1 μF. It is connected to an ac variable frequency source of peak voltage 10 V. At resonance the power supplied by the source will be
63590. In figure, the power associated with 3 A source is
63591. In the circuit shown in figure the inductor current and capacitor voltage are given at a time t. At this instant i is __________ A and is __________ A/sec.
63592. In the Bode plot, of , the phase at w = 15 is
63593. The inductance of an air cored coil is 2 H. The number of turns is made 3 times, all other quantities remaining the same. The new value of inductance will be 2 2
63594. j6 =
63595. A loudspeaker transformer has a turns ratio of 20 : 1. The speaker impedance is 20Ω. Primary impedance of transformer is
63596. For splicing tension reinforcement in flexural members,the most suitable location is:
63597. Assertion (A): The polynomial s3 + 6s2 + 12s + 8 is Hurwitz.Reason (R): In a Hurwitz polynomial all coefficients are non-negative.
63598. A dc network has an open circuit voltage of 5 V. When its terminals are short circuited a current of 5 A flows through the short circuit. If the short circuit is removed and a resistance of 1.5 Ω is connected across its terminals, the current will be
63599. A coil of resistance R and inductance L has a capacitor C in parallel with it. The source frequency is adjusted to a value equal to resonant frequency. Another capacitor C is added in parallel with the above circuit, the source current will
63600. In the circuit of figure the current through 3 Ω resistance at t = ∞ is