Question Set

1. If the head is doubled in & centrifugal pump, the power required will increase in the ratio of





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The ratio of bases of a cylinder and a cone are in the ratio 3: Volume of cylinder and cone are in the ratio 9: then their heights are in the ratio?....
QA->If the sides of a square are doubled. Then its area will increase/decrease by how much percentage....
QA->The process of adjusting the quantity of fuel delivered by the fuel injection pump is:....
QA->In a mixture of 35 litres, the ratio of milk and water is 5 : Another 5 litres of milk is added to the mixture. The ratio of milk and water in the new mixture is—....
QA->Present ages of Kiran and Syam are in the ratio of 5:4 respectively. Three years hence, the ratio of their ages will become 11:9 respectively. What is Syam"s present age in years?....
MCQ->If the head is doubled in & centrifugal pump, the power required will increase in the ratio of....
MCQ->What will be the output of the program? #include<stdio.h> int main() { int i=4, j=-1, k=0, w, x, y, z; w = i || j || k; x = i && j && k; y = i || j &&k; z = i && j || k; printf("%d, %d, %d, %d\n", w, x, y, z); return 0; }....
MCQ->A centrifugal pump designed to pump water is employed to pump a more viscous oil. In the later case, the pump....
MCQ->In case of a, centrifugal pump, the ratio h1/h2 is termed as the __________ efficiency (where, h1 = actual measured head & h2 = head imparted to the fluid by impeller).....
MCQ->A centrifugal pump is used to pump water through a horizontal distance of 150 m, and then raised to an overhead tank 10 m above. The pipe is smooth with an I.D of 50 mm. What head (m of water) must the pump generate at its exit (E) to deliver water at a flow rate of 0.001 m3/s? The Fanning friction factor, f is 0.0062. ....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution