In case of a pipe of constant cross-sectional area, the maximum fluid velocity obtainable is ?->(Show Answer!)

Question Set

1. In case of a pipe of constant cross-sectional area, the maximum fluid velocity obtainable is

Show Similar Question And Answers

QA->The process of transfer of heat from one point of a fluid to another part of a fluid by the movement of fluid itself is called?....

QA->When a fluid passes through the constricted part of a pipe its?....

QA->For a body moving with constant speed in a horizontal circle; what remains constant?....

QA->For a body moving with constant speed in a horizontal circle, what remains constant?....

QA->A train of length 150 meters took 8 seconds to cross a bridge of length 250 meters. Time taken by the train to cross a telephone post is....

MCQ->In case of a pipe of constant cross-sectional area, the maximum fluid velocity obtainable is....

MCQ->What will be the output of the C#.NET code snippet given below? char ch = Convert.ToChar ('a' | 'b' | 'c'); switch (ch) { case 'A': case 'a': Console.WriteLine ("case A | case a"); break; case 'B': case 'b': Console.WriteLine ("case B | case b"); break; case 'C': case 'c': case 'D': case 'd': Console.WriteLine ("case D | case d"); break; }....

MCQ->A pipe of 0.1 m2 cross sectional area suddenly enlarges to 0.3 m2 cross-sectional area. If the discharge of the pipe is 0.3 m3 /sec, the head loss is....

MCQ->The pressure drop per unit length of pipe incurred by a fluid 'X' flowing through pipe is Δp. If another fluid 'Y' having both the specific gravity & density just double of that of fluid 'X', flows through the same pipe at the same flow rate/average velocity, then the pressure drop in this case will be....

MCQ->The pressure drop per unit length for laminar flow of fluid through a long pipe is proportional to (where, A = cross-sectional area of the pipe & D = Diameter of the pipe)....

Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions Question ANSWER With Solution