1. A stone is whirled in a vertical circle, the tension in the string, is maximum





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->It is easier to roll a stone up a sloping road than to lift it vertical upwards because?....
QA->Post and Telegraph circle got bifuricated and Kerala Postal Circle came into existence in?....
QA->A steel wire when bent in the form of a square encloses an area of 121 sq. cm. If the same wire is bent into the form of a circle, the area of the circle is—....
QA->Energy stored in a compressed string is?....
QA->What is the vertical component of earth’s magnetic field?....
MCQ->A stone is whirled in a vertical circle, the tension in the string, is maximum....
MCQ->A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is,....
MCQ->Which of the following snippets are the correct way to convert a Single into a String? Single f = 9.8f; String s; s = (String) (f); Single f = 9.8f; String s; s = Convert.ToString(f); Single f = 9.8f; String s; s = f.ToString(); Single f = 9.8f; String s; s = Clnt(f); Single f = 9.8f; String s; s = CString(f);....
MCQ->One end of a string is connected to an electrically maintained vibrating bar while the other end is made to pass over a frictionless pulley.The free end is then loaded so that the string is under tension TThe string vibrates in X1 segments as the bar vibrates in transverse mode.If the tension is changed to T2 the string vibrates in x2 segments.Then:....
MCQ->Which of the following is correct way to convert a String to an int? String s = "123"; int i; i = (int)s; String s = "123"; int i; i = int.Parse(s); String s = "123"; int i; i = Int32.Parse(s); String s = "123"; int i; i = Convert.ToInt32(s); String s = "123"; int i; i = CInt(s);....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution