1. The combination of a short circuit in series with an open circuit always results in a(n) ________ circuit.





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->At the time of short-circuit; what will be the current in the circuit?....
QA->At the time of short-circuit, what will be the current in the circuit?....
QA->Short circuit means?....
QA->A short but pithy and weightily saying, a short witty phrase....
QA->"Period. End of Sentence" has won the Best Documentary Short Subject award at the Oscar The short film is produced by which Indian producer?....
MCQ->The combination of a short circuit in series with an open circuit always results in a(n) ________ circuit.....
MCQ->Match the following: List I (Form) List II (Network) A.Cauer I1.L in series arm and C in shunt arm of ladderB.Cauer II2.C in series arm and L in shunt arm of ladderC.Foster I3.Series combination of L and C in parallelD.Foster II4.Parallel combination of L and C in series

....
MCQ->What will be the output of the program? public class WrapTest { public static void main(String [] args) { int result = 0; short s = 42; Long x = new Long("42"); Long y = new Long(42); Short z = new Short("42"); Short x2 = new Short(s); Integer y2 = new Integer("42"); Integer z2 = new Integer(42); if (x == y) / Line 13 / result = 1; if (x.equals(y) ) / Line 15 / result = result + 10; if (x.equals(z) ) / Line 17 / result = result + 100; if (x.equals(x2) ) / Line 19 / result = result + 1000; if (x.equals(z2) ) / Line 21 / result = result + 10000; System.out.println("result = " + result); } }....
MCQ->A dc network has an open circuit voltage of 5 V. When its terminals are short circuited a current of 5 A flows through the short circuit. If the short circuit is removed and a resistance of 1.5 Ω is connected across its terminals, the current will be....
MCQ->Which one is correct statement? Circuit is always openNetwork is always openCircuit is always closedNetwork is always closed....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution