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1. 476 0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's places are respectively:





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  • By: guest on 01 Jun 2017 05.46 pm
    Let the given number be 476 xy 0. Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3. And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11. x - y - 3 = 0    y = x - 3 (17 + x + y) = (17 + x + x - 3) = (2x + 14) x= 2 or x = 8. x = 8 and y = 5.
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