1. A half wave diode rectifier uses a diode having forward resistance of 50 ohms. The load resistance is also 50 ohms. Then the voltage regulation is





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 01 Jun 2017 11.43 pm
    No load output voltage = Output voltage at full load = .
Show Similar Question And Answers
QA->The device used for converting current from a lower voltage to a higher voltage is known as?....
QA->A man is facing East, then the turns left and goes 10 m, then turns right and goes 5 m, then goes 5 m to the South and from there 5 m to West. In which direction is he, from his original place ?....
QA->Long distance short-wave radio broad casting uses which waves?....
QA->A wave motion in which the particles of the medium vibrate parallel to the direction of propagation of wave is?....
QA->When the frequency of the sound wave is increased, what happens to its wave length?....
MCQ->A half wave diode rectifier uses a diode having forward resistance of 50 ohms. The load resistance is also 50 ohms. Then the voltage regulation is....
MCQ->A full wave diode rectifier using centre tapped transformer has diodes with forward resistance of 50 ohms each. The load resistance of 50 ohms each. The load resistance is also 50 ohms. The voltage regulation is....
MCQ->Consider the following rectifier circuits : half-wave rectifier without filterfull-wave rectifier without filterfull-wave rectifier with series inductance filterfull-wave rectifier with capacitance filter. The sequence of these rectifier circuits in decreasing order of their ripple factor is....
MCQ->A full wave bridge diode rectifier uses diodes having forward resistance of 50 ohms each. The load resistance is also 50 ohms. The voltage regulations is....
MCQ->Assertion (A): A half wave controlled rectifier has poorer efficiency and higher ripple factor than a full wave controlled rectifier.Reason (R): The use of a freewheeling diode in half wave controlled rectifier circuit improves the waveform of load current and circuit power factor.

....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution