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1. Leakage current approximately doubles for every 10°C increase in the temperature of a transistor has ICBO = 400 nA at 25°C, then its leakage current at 80°C





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  • By: guest on 01 Jun 2017 11.43 pm
    ICBO = (400 x 10-9) 2(80-25)/10 = 18 μA.
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