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1. In the following figure C = 0.02 μF, and Vth is known to be of frequency ω = 107 rad/sec and rd = 2.5 Ω and ZTh = RTh = 10 Ω Then phase angle between id and Vd





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  • By: guest on 01 Jun 2017 11.43 pm
    Zd = (rd)11 (-jxd) 2 - JΩ θ = tan-1 (-1/2) 26.56 .
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