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electronics and communication engineering analog electronics
1. In figure, ID = 4 mA. Then VDS =
(A): 0.4 V
(B): 16 V
(C): 20 V
(D): 4 V
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By: guest on 01 Jun 2017 11.43 pm
VDS = VD - VS = 10-6 = 4 V.
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