1. In an amplifier if conductor during the cycle is from 0 to 90° and again from 180° to 270°, the amplifier will be termed as





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->A cyclist goes 40 km towards East and then turning to right he goes 40 km. Again he turn to his left and goes 20 kn. After this he turns to his left and goes 40 km, then again turns right and goes 10 km. I-low far is he from his starting point ?....
QA->Again and again....
QA->John started from his home and walked 12 km.Then he took a right turn and walked 4 km.Then again,he took a right turn and walked 8 km and finally took another right turn and walked 1 km.How far is he from his home now?....
QA->Arjun walks 2 kms northwards and then he turns right and moves 3 kms. He again turns right and goes 2 kms and turns his left and starts walking straight. In which direction he is walking now ?....
QA->Arjun walks 2 kms northwards and then he turns right and moves 3 kms. He again turns right and goes 2 kms and turns his left and starts walking straight. In which direction he is walking now ?....
MCQ->In an amplifier if conductor during the cycle is from 0 to 90° and again from 180° to 270°, the amplifier will be termed as....
MCQ->If carrier is modulated by a digital bit stream having one of the possible phases of 0°, 90°, 180°, and 270°, then modulation is called....
MCQ->If the carrier modulated by a digital bit stream has one of the possible phases of 0°, 90°, 180° and 270°. Then the modulation is called....
MCQ->If carrier modulated by a digital bit stream had one of the possible phases of 0°, 90°, 180°, 270°, then the modulation is called.....
MCQ->There are 3 friends.B and Each of them have a Hat and a Cycle.Each of them is wearing another person’s hat and riding the cycle of the third person(i.e.None of them is using their own hat and cycle).If A is wearing B’s hat and riding C’s cycle,who is riding A’s cycle?....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution