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1. The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
(A): 28
(B): 32
(C): 40
(D): 64
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By: guest on 01 Jun 2017 05.48 pm
Let the numbers be 2x and 3x. Then, their L.C.M. = 6x. So, 6x = 48 or x = 8. The numbers are 16 and 24. Hence, required sum = (16 + 24) = 40.
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