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1. A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
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By: guest on 01 Jun 2017 05.48 pm
Let the length of the train be x metres and its speed by y m/sec. Then, x = 8 x = 8y y Now, x + 264 = y 20 8y + 264 = 20y y = 22. Speed = 22 m/sec = 22 x 18 km/hr = 79.2 km/hr. 5