1. A (75 - j 40) W load is connected to a co-axial line of z0 = 75ω at 6 MHz. The load matching on the line can be accomplished by connecting





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  • By: guest on 02 Jun 2017 12.49 am
    ZL = 75 - J . 40, ZC = 75 W, f = 6 mHz Given ZL is capacitive, so proper matching, load must be inductive.
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