Question Set

1. For a 400 kHz transmission line having L = 0.5 mH/km, C = 0.08 mF and negligible R and G, the value of propagation constant P will be





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 02 Jun 2017 12.49 am
    γ = a + jβ, a = 0 β = ωLC .
Show Similar Question And Answers
QA->The range of electromagnetic spectrum between 10 KHz and 1 GHz is called:....
QA->For a body moving with constant speed in a horizontal circle; what remains constant?....
QA->For a body moving with constant speed in a horizontal circle, what remains constant?....
QA->In which mode of transmission, the heat waves travel along the straight line with the speed of light?....
QA->A line that indicates equal or constant pressure on a map is called ____?....
MCQ->For a 400 kHz transmission line having L = 0.5 mH/km, C = 0.08 mF and negligible R and G, the value of propagation constant P will be....
MCQ->For a 400 kHz transmission line having L = 0.5 mH/km, C = 0.08 mF and negligible R and G, the velocity propagation will be....
MCQ->For a 400 kHz transmission line having L = 0.5 mH/km, C = 0.08 mF and negligible R and G, the characteristic impedance will be....
MCQ->A superheterodyne receiver is to operate in the frequency range 550 kHz - 1650 kHz, with the intermediate frequency of 450 kHz. Let denote the required capacitance ratio of the local oscillator and I denote the image frequency (in kHz) of the incoming signal. If the receiver is tuned to 700 kHz, then....
MCQ->Match the following: List I List II A.Evanescent wave1.Pattern multiplicationB.Skip distance2.Mismatched transmission lineC.Return loss3.Propagation in lossy mediumD.Antenna array4.Short wave propagation 5.Propagation below cut-off

....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution