1. The voltage across the secondary of the transformer in a half wave rectifier with a shunt capacitor filter is 50 volts. The maximum voltage that will occur on the reverse biased diode will be





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The device used for converting current from a lower voltage to a higher voltage is known as?....
QA->To be biased against....
QA->Which part of our body filter urea from blood?....
QA->The production of ail electromotive force (voltage) across an electrical conductor due to its dynamic interaction with a magnetic field is called?....
QA->The thickness of certain ceramics changes when a voltage is applied across them this property is called?....
MCQ->The voltage across the secondary of the transformer in a half wave rectifier with a shunt capacitor filter is 50 volts. The maximum voltage that will occur on the reverse biased diode will be....
MCQ->The voltage across the secondary of the transformer in a half wave rectifier (without any filter circuit) is 25 volts. The maximum voltage on the reverse biased diode will be....
MCQ->Consider the following rectifier circuits : half-wave rectifier without filterfull-wave rectifier without filterfull-wave rectifier with series inductance filterfull-wave rectifier with capacitance filter. The sequence of these rectifier circuits in decreasing order of their ripple factor is....
MCQ->If 100 V is the peak voltage across the secondary of the transformer in a half-wave rectifier (without any filter circuit), then the maximum voltage on the reverse-biased diode is....
MCQ->If 10 V is the peak voltage across the secondary of the transformer in a half wave rectifier (without any filter circuit), then the maximum voltage on the reverse biased diode will be....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution