1. If ω0 is the angular frequency of rotation of electron in the absence of magnetic field, the angular frequency ω, when a magnetic field B is acting is ω ≅ ω0 + (e/2m)B.



Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The radiation which is not affected by the magnetic field or electric field is?....
QA->The number of waves made by an electron moving in an orbit having maximum magnetic quantum number is +3?....
QA->When do all the magnetic materials lose their magnetic properties?....
QA->What is the vertical component of earth’s magnetic field?....
QA->How are the magnetic field lines in the middle of a solenoid?....
MCQ->If ω0 is the angular frequency of rotation of electron in the absence of magnetic field, the angular frequency ω, when a magnetic field B is acting is ω ≅ ω0 + (e/2m)B.....
MCQ->Assertion (A): When an electron is revolving in its orbit and magnetic field is also present, the angular frequency of electron will be affected by the magnetic field.Reason (R): In the case of electron revolving in its orbit in the presence of magnetic field, the orbital magnetic dipole moment is not affected by the presence of magnetic field.

....
MCQ->If q is charge on an electron, R is radius of electron orbit and ω is angular velocity of electron rotation, the magnetic dipole moment of electron in orbit is....
MCQ->Consider the following statements for a driving point function F(jω): Re F(jω) is an even function of ω and is 0 or positive for all values of ω.Im F(jω) is an even function of ω and is 0 or positive for all values of ω.Re F(jω) is an odd function of ω and is 0 or negative for all values of ω.Re F(s) = 0 for Re s = 0. Which one of the statements given above is/are correct?....
MCQ->Assertion (A): If an electron having charge e is revolving in an orbit of radius R and with angular velocity ω, the magnetic dipole moment of orbit is 0.5 eωR2.Reason (R): Orbital angular momentum and magnetic dipole moment are always equal.

....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution