1. Two ammeters A and B are connected in parallel in a circuit carrying 100 A. Their resistances are 0.8 mΩ. Their readings will be.





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 02 Jun 2017 01.01 am
    .
Show Similar Question And Answers
QA->.If three resistances 6 ohm,4 ohm and 3 ohm are connected in parallel,what will be the total resistance?....
QA->To make a notebook act as a desktop model, the notebook can be connected to a ………………….. which is connected to a monitor-and other devices.....
QA->At the time of short-circuit; what will be the current in the circuit?....
QA->At the time of short-circuit, what will be the current in the circuit?....
QA->Which among the following women of Kerala participated in the Civil Disobedience Movement, carrying two month old baby in her arms and led the procession of Women?....
MCQ->Two ammeters A and B are connected in parallel in a circuit carrying 100 A. Their resistances are 0.8 mΩ. Their readings will be.....
MCQ->Two ammeters having resistances of 0.5 Ω and 0.25 Ω and having full scale reading of 25 A each are connected in parallel. To ensure that neither of them goes beyond scale, the total current should not be more than....
MCQ->Two voltmeters are each 0-300 V range. Their internal resistances are 10 kΩ and 20 kΩ They are connected is series and a voltage of 400 V is applied. Their readings respectively will be....
MCQ->A 3-ohm resistor is connected is parallel to 6-ohm resistor.The combination is connected in series to an 8-ohm resistor.A 10-ohm resistor is connected in parallel to the whole combination.The effective resistance is:....
MCQ->Two ammeters A and B both 0-10 A have internal resistance of 1 Ω and 0.5 Ω respectively. They are connected in parallel. If total current is 15 A, then....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution