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1. In figure, the capacitor is charged to 1 V. At t = 0 the switch is closed so that i = e-t. When i = 0.37 A, the voltage across capacitor is
(A): 0.185 V
(B): 0.37 V
(C): 0.63 V
(D): 1 V
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By: guest on 02 Jun 2017 01.06 am
During discharge of capacitor vC = vR = 0.37 x 1 = 0.37 V
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