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electronics and communication engineering networks analysis and synthesis
1. Two voltages are 50 ∠0 V and 75 ∠ - 60° V. The sum of these voltages is
(A): 100 ∠ - 50.1° V
(B): 109 ∠ - 25° V
(C): 109 ∠ - 36.6° V
(D): 109 ∠ - 60° V
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Comments
By: guest on 02 Jun 2017 01.06 am
50Ð0 = 50 + j 0.75∠-60° = 37.5 - j 64.95 Sum = (50 + 37.5) - j 64.95 = 87.5 - j 64.95 = 109∠-36.6°
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