1. The voltage of the source in circuit shown __________ if i(t) = - 20e-2t is





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  • By: guest on 02 Jun 2017 01.07 am
    Voltage across capacitor = i(t) x 1 - 20 e-2t Current across capacitor = 120 e-2t Source current Is = iC (t) + iR(t) 120 e-2t - 20e-2t 100 e-2t VR = 100 e-2t 33.33 e-2t, Vs = 100 e-2t - 20 e-2t - 33.33 e-2t Vs = 46.6 e-2t volt.
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