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1. The analog signal m(t) is given below m(t) = 4 cos 100 p t + 8 sin 200 p t + cos 300 p t, the Nyquist sampling rate will be





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  • By: guest on 02 Jun 2017 01.13 am
    m (t) = 4 cos 100 p t + 8 sin 200 p t + cos 300 p t Nyquist sampling freq fs ≤ 2fm where fm is highest frequency component in given signal and highest fm in 3rd part 2p fmt = 300 p t fm = 150 Hz fs = 2 x 150 p 300 Hz .
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