Question Set

1. Tin base white metals are used where the bearings are subjected to





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The scientist who classified elements into Metals and Non-metals is?....
QA->Elements showing properties of both metals and non-metals are?....
QA->Who Classified Elements as Metals and non-metals?....
QA->The study of metals and the overall process by which metals are extracted from its ores are called?....
QA->The elements which show the properties of both metals and non metals are called?....
MCQ->Tin base white metals are used where the bearings are subjected to....
MCQ->Tin based white metals are used, where bearings are subjected to....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { int x, y; public: Base() { x = y = 0; } Base(int xx) { x = xx; } Base(int p, int q = 10) { x = p + q; y = q; } void Display(void) { cout<< x << " " << y << endl; } }objDefault(1, 1); class Derived: public Base { Base obj; public: Derived(int xx, int yy): Base(xx, xx + 1) { } Derived(Base objB = objDefault) { } }; int main() { Derived objD(5, 3); Derived ptrD = new Derived(objD); ptrD->Display(); delete ptrD; return 0; }....
MCQ->Tin base and lead base alloys are used for bearing materials. Tin compared to lead has lower....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { public: int S, A, M; Base(int x, int y) { S = y - y; A = x + x; M = x x; } Base(int, int y = 'A', int z = 'B') { S = y; A = y + 1 - 1; M = z - 1; } void Display(void) { cout<< S << " " << A << " " << M << endl; } }; class Derived : public Base { int x, y, z; public: Derived(int xx = 65, int yy = 66, int zz = 67): Base(x) { x = xx; y = yy; z = zz; } void Display(int n) { if(n) Base::Display(); else cout<< x << " " << y << " " << z << endl; } }; int main() { Derived objDev; objDev.Display(-1); return 0; }....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution