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What will be the output of the program? #include<stdio.h> #define SWAP(a, b) int t; t=a, a=b, b=t; int main() { int a=10, b=12; SWAP(a, b); printf("a = %d, b = %d\n", a, b); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> #define SWAP(a, b) int t; t=a, a=b, b=t; int main() { int a=10, b=12; SWAP(a, b); printf("a = %d, b = %d\n", a, b); return 0; }




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  • By: guest on 01 Jun 2017 06.00 pm
    The macro SWAP(a, b) int t; t=a, a=b, b=t; swaps the value of the given two variable. Step 1: int a=10, b=12; The variable a and b are declared as an integer type and initialized to 10, 12 respectively. Step 2: SWAP(a, b);. Here the macro is substituted and it swaps the value to variable a and b. Hence the output of the program is 12, 10.
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