1. Trouton's ratio of __________ liquids is calculated using Kistyakowsky equation.





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The ratio of bases of a cylinder and a cone are in the ratio 3: Volume of cylinder and cone are in the ratio 9: then their heights are in the ratio?....
QA->Method of cultivating plants without using soil but by using nutrient solution?....
QA->In a mixture of 35 litres, the ratio of milk and water is 5 : Another 5 litres of milk is added to the mixture. The ratio of milk and water in the new mixture is—....
QA->Present ages of Kiran and Syam are in the ratio of 5:4 respectively. Three years hence, the ratio of their ages will become 11:9 respectively. What is Syam"s present age in years?....
QA->P യും Q യും തമ്മിലുള്ള ratio 6: Q ന് p യെക്കാൾ 4 വയസ് അധികം ഉണ്ട് . എങ്കിൽ 4 വർഷം കഴിഞ്ഞു p:Q തമ്മിലുള്ള ratio എത്ര ?....
MCQ->Trouton's ratio of __________ liquids is calculated using Kistyakowsky equation.....
MCQ->The value of Trouton's ratio (λb/Tb) for a number of substances is 21 (where, λb = molal that of vaporisation of a substance at its normal boiling point, KCal/kg. mole and Tb = normal boiling point, °K). The Kis-tyakowsky equation is used for calculation of Trouton's ratio of __________ liquids.....
MCQ->Which of the following equations are used for the derivation of the differential equation for water surface profile in open channel flow : 1. Continuity equation 2. Energy equation 3. Momentum equation Select the correct answer using the codes given below : ....
MCQ->Energy loss due to friction in laminar flow can be calculated either using Darcy’s equation or Hagen-Poiseuille equation where friction factor is:....
MCQ->Trouton's ratio is given by (where λb, = molal heat of vaporisation of a substance at its normal boiling point, kcal/kmol Tb = normal boiling point, °K )....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution