1. In the graphical analysis of CE amplifier circuit, the intersection of base current and dc load line is called





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QA->A man who can swim 48 m/minute in still water. He swims 200 m against the current and 200 m with the current. If the difference between those two times is 10 minutes, what is the speed of the current?....
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MCQ->In the graphical analysis of CE amplifier circuit, the intersection of base current and dc load line is called....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { int x, y; public: Base() { x = y = 0; } Base(int xx) { x = xx; } Base(int p, int q = 10) { x = p + q; y = q; } void Display(void) { cout<< x << " " << y << endl; } }objDefault(1, 1); class Derived: public Base { Base obj; public: Derived(int xx, int yy): Base(xx, xx + 1) { } Derived(Base objB = objDefault) { } }; int main() { Derived objD(5, 3); Derived ptrD = new Derived(objD); ptrD->Display(); delete ptrD; return 0; }....
MCQ->In the graphical analysis of CE amplifier circuit, the upper end of load line is called....
MCQ->In graphical analysis of BJT amplifier the slope of ac line is more than that of dc load line.....
MCQ->What will be the output of the program? class Base { Base() { System.out.print("Base"); } } public class Alpha extends Base { public static void main(String[] args) { new Alpha(); / Line 12 / new Base(); / Line 13 / } }....
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