1. The number of digit 1 present in the binary representation of 3 x 512 + 7 x 64 + 5 x 8 + 3 is





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  • By: guest on 01 Jun 2017 05.53 pm
    3 x 512 + 7 x 64 + 5 x 8 + 3 = (2 + 1) x 29 + (4 + 2 + 1)26 + (4 + 1)23 + (2 + 1) = 210 + 29 + 28 + 27 + 26 + 25 + 23 + 21 + 1 = 210 + 29 + 28 + 27 + 26 + 25 + 23 + 21 + 20 9 term of power two Hence number of '1' is 9.
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