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electronics and communication engineering networks analysis and synthesis
1. The VTH at terminals A and B is equal to
(A): -5 V
(B): 0 V
(C): 5 V
(D): none
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Comments
By: guest on 02 Jun 2017 01.07 am
Apply KVL to loop 1 5V - 3I1 - 2 (I1 - I2) - 5V = 0 ∴ I2 = 0 5V - 5V - 5I1 = 0 I1 = 0 ∴ VAB = 5 volt.
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