1. In the circuit, S was initially open. At time t = 0, S is closed. When the current through the inductor is 6 A, the rate of change of current through the resistor is 6 A/s. The value of the inductor would be





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  • By: guest on 02 Jun 2017 01.07 am
    i = 18(1 - e-t/L) ...(1) 6 = 8 (1 - e-t/L) 1 = 3 (1 - e-t/L) 1 = 3 - 3 e-t/L e-t/L = 2/3 from (1) .
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