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1. In an R-L circuit excited by a battery of voltage E, the current and voltage across resistor are 1- e-t and 2(1 - e-t) respectively. If there were an initial current of 2 A in the inductance, the voltage across resistance would have been





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  • By: guest on 02 Jun 2017 01.07 am
    From the given data R = 2Ω, L = 2H and E = 2V. Because of initial current of 2A, i(t) = 1 - e-t + 2e-t = 1 + e-t. Therefore, VR = 2(1 + e-t).
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