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electrical engineering series circuits
1. A certain series circuit consists of a 1/8 W resistor, a 1/4 W resistor, and a 1/2 W resistor. The total resistance is 1200 . If each resistor is operating in the circuit at its maximum power dissipation, total current flow is
(A): 19 mA
(B): 190 mA
(C): 2.7 mA
(D): 27 mA
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By: guest on 01 Jun 2017 11.29 pm
Total P = P1 + P2 + P3 = 7/8w.
P = I2R.
I = sqrt (P/R)
Now, P = 7/8w, R = 1200 ohm.
Therefore,
I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.
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Question ANSWER With Solution
P = I2R.
I = sqrt (P/R)
Now, P = 7/8w, R = 1200 ohm.
Therefore,
I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.