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1. An RL series circuit is initially relaxed. A step voltage E is applied. If t is time constant, voltage across R and L will be equal at t =
(A): t ln 2
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By: guest on 02 Jun 2017 01.07 am
vR = E(1 - e-t/t ) and vL = E e-t/t or 1 - e-t/t = e-t/t. This happens at t = t in 2.
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