In an R-L-C circuit, v(t) = 20 sin (314 t + 5 p /6) and i(t) = 10 sin (314 t + 2p /3). The p.f of the circuit is ?->(Show Answer!)

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1. In an R-L-C circuit, v(t) = 20 sin (314 t + 5 p /6) and i(t) = 10 sin (314 t + 2p /3). The p.f of the circuit is

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1. In an R-L-C circuit, v(t) = 20 sin (314 t + 5 p /6) and i(t) = 10 sin (314 t + 2p /3). The p.f of the circuit is

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