Question Set

1. For an involute gear, the ratio of base circle radius and pitch circle radius is equal to





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The ratio of bases of a cylinder and a cone are in the ratio 3: Volume of cylinder and cone are in the ratio 9: then their heights are in the ratio?....
QA->In an automobile gear transmission the counter shaft drive gear is meshed with the gear on the:....
QA->The ratio between the radius of the base and the height of a cylinder is 2 : If its volume is 1617 cm3, the total surface area of the cylinder is—....
QA->Post and Telegraph circle got bifuricated and Kerala Postal Circle came into existence in?....
QA->In a mixture of 35 litres, the ratio of milk and water is 5 : Another 5 litres of milk is added to the mixture. The ratio of milk and water in the new mixture is—....
MCQ->For an involute gear, the ratio of base circle radius and pitch circle radius is equal to....
MCQ->Gear A has a weight of 1.5 lb, a radius of 0.2 ft, and a radius of gyration of ko = 0.13ft. The coefficient of friction between the gear rack B and the horizontal surface is = 0.3. If the rack has a weight of 0.8 lb and is initially sliding to the left with a velocity of (vB)2 = 8 ft/s to the left. Neglect friction between the rack and the gear and assume that the gear exerts only a horizontal force on the rack.....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { int x, y; public: Base() { x = y = 0; } Base(int xx) { x = xx; } Base(int p, int q = 10) { x = p + q; y = q; } void Display(void) { cout<< x << " " << y << endl; } }objDefault(1, 1); class Derived: public Base { Base obj; public: Derived(int xx, int yy): Base(xx, xx + 1) { } Derived(Base objB = objDefault) { } }; int main() { Derived objD(5, 3); Derived ptrD = new Derived(objD); ptrD->Display(); delete ptrD; return 0; }....
MCQ->If RADIUS = 3.0 the result of the following FORTRAN 77 program will be

REAL RADIUS, CAREA, SAREA, RATIO
PI
PI = 3.1416
READ , RADIUS CAREA = PI RADIUS RADIUS
SAREA = 2 RADIUS RADIUS
RATIO = CAREA/SAREA....
MCQ->In a gear, having involute teeth, the normal to the involute is a tangent to the....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution