1. In the op-amp circuit of figure, V0 =





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 01 Jun 2017 11.42 pm
    .
Show Similar Question And Answers
QA->At the time of short-circuit; what will be the current in the circuit?....
QA->At the time of short-circuit, what will be the current in the circuit?....
QA->How much distance does the earth’s annual circuit round the sun cover?....
QA->Which is electrical circuits used to get smooth de output from a rectified circuit called?....
QA->ഐ.സി ചിപ്പ് (integrated circuit chips) നിർമ്മിക്കാൻ ഉപയോഗിക്കുന്ന മൂലകങ്ങൾ?....
MCQ->What will be the output of the program? #include<stdio.h> int main() { int i=4, j=-1, k=0, w, x, y, z; w = i || j || k; x = i && j && k; y = i || j &&k; z = i && j || k; printf("%d, %d, %d, %d\n", w, x, y, z); return 0; }....
MCQ->Which of the following statements are correct about the Bitwise & operator used in C#.NET? The & operator can be used to Invert a bit. The & operator can be used to put ON a bit. The & operator can be used to put OFF a bit. The & operator can be used to check whether a bit is ON. The & operator can be used to check whether a bit is OFF.....
MCQ->Pick out thể one word for - a secret arrangement....
MCQ->What will be the output of the program? #include<stdio.h> int main() { int i=-3, j=2, k=0, m; m = ++i && ++j && ++k; printf("%d, %d, %d, %d\n", i, j, k, m); return 0; }....
MCQ->What will be the output of the program? #include<stdio.h> int main() { char ch; ch = 'A'; printf("The letter is"); printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch); printf("Now the letter is"); printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A'); return 0; }....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution