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1. For a npn BJT transistor fβ is 1.64 x 108 Hz. Cμ = 10-14 F; Cp = 4 x 10-13 F and DC current gain is 90. Find fT and gm (fβ = cut off frequency, Cμ = capacitance, Cp = parasitic capacitance, gm = transconductance, fT = gain BW product)





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  • By: guest on 02 Jun 2017 12.54 am
    ∴ fT = 90 x 1.64 x 108 = 1.47 x 1010 Hz gm = 2p fT(Cμ + Cp ) = 2 x p x 1.47 x 1010 = (10-14 + 4 x 10-13) gm= 38 mμ.
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