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1. The current through a 1 mH inductance is i(t) = 2.56 x 10-2 - 4 x 103 t for 2 ≤ t ≤ 20 μ sec. The voltage across the inductor is





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  • By: guest on 02 Jun 2017 01.07 am
    1 x 10-3 (2.56 x 10-2 - 4 x 103t) = 1 x 10-3 x 4 x 103 4 volt.
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