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1. What will be the output of the program? int i = (int) Math.random();





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  • By: guest on 02 Jun 2017 01.26 am
    Math.random() returns a double value greater than or equal to 0 and less than 1. Its value is stored to an int but as this is a narrowing conversion, a cast is needed to tell the compiler that you are aware that there may be a loss of precision. The value after the decimal point is lost when you cast a double to int and you are left with 0.
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